How is the field of view calculated for the B-mode image generation? I see in the code the following in the plotting code:
sound_speed_map(:, 1 + Ny/2:end - Ny/2, Nz/2)So the transducer was set to be at the midpoint. So, should the field of view not be something like:
startIdx = Ny/2 - transducer_width/2
sound_speed_map(:, startIdx:startIdx + transducer_width, Nz/2)Would really appreciate any clarification on this.
I hope someone can reply to this query as I am quite confused.
So the transducer is put in the centre of the computation grid.The width of the FOV is the number of scan lines * width of the element.
However, I am confused as to why the FOV starts at 1 + Ny/2 rather than 1 + Ny/2 - transducer_width / 2.
Have you looked at the documentation? In short, a larger phantom is defined, and only a subset of this is used for each simulation to improve computational speed.
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