k-Wave

1. wang_feng_2020
   

   Member
   Joined: Mar '20
   Posts: 6

   Hi,Brad.
   Here is my code:

   % muscle
   medium.sound_speed = 1588 * ones(Nx,Ny); % [m/s]
   medium.density = 1090 * ones(Nx, Ny); % [kg/m^3]
   medium.alpha_coeff = 0.6*ones(Nx,Ny); % [dB/(MHz^y cm)]
   medium.BonA = 7.8*ones(Nx,Ny);
   medium.alpha_power =1.2;

   Theoretically, the higher the frequency of the source, the greater the attenuation factor.
   When the frequency of the source is 1MHz, the attenuation is -82dB. When the frequency of the source is 2MHz, the attenuation is -76dB.

   This is the opposite of the theoretical calculation,Why does this happen?

   Posted 4 years ago #

2. Bradley Treeby
   

   Developer
   Joined: Mar '10
   Posts: 1,643

   Hi wang_feng_2020,

   Unfortunately, it's impossible to say without seeing the rest of your code. One comment, attenuations on the order of -80 dB are very large, and about the same performance as the PML used in k-Wave. It's possible that you've reached the noise floor.

   Brad.

   Posted 4 years ago #

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